.01x^2=36

Solution for .01x^2=36 equation:

.01x^2=36

We move all terms to the left:

.01x^2-(36)=0

a = .01; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·.01·(-36)
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.44}}{2*.01}=\frac{0-\sqrt{1.44}}{0.02}
=-\frac{\sqrt{}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.44}}{2*.01}=\frac{0+\sqrt{1.44}}{0.02}
=\frac{\sqrt{}}{0.02}
$